find the roots of following quadratic equation ; (x+3) (x-1) = 3(x-1/3)
please help me !!
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x2 + 2x -3 = 3x -1
x2 - x -2 =0
x2 - 2x +x -2 = 0
x(x-2) +1 (x-2) = 0
(x-2) (x+1) = 0
roots = 2, -1
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