Question

find the roots of following quadratic equations by factorisation
2x^2-x+1/8
please it's very very urgent​

Answer 1

Step-by-step explanation:

• first multiply 8 by both sides.
• then find the factors.
• take the common .
• then u will get the roots.

Answer 2

2x^2-x+1/8

=(16x^2-8x+1)/8

= [16x^2-(4+4)x+1]/8

=[16x^2-4x-4x+1]/8

=[4x(4x-1)-1(4x-1)]/8

=[(4x-1)(4x-1)]/8

=(4x-1)/8.(4x-1)

=[4x/8-1/8].(4x-1)

=[x/2-1/8].(4x-1)

x/2-1/8=0 or 4x-1=0

x=2/8 or 4x=

answer;{x=1/4}