Math, asked by mihikajain04p8syha, 6 months ago

find the roots of :-
(i) √3x² -5x+√3
(ii) 4x²-4x-2​

Answers

Answered by amjadmd786786
1

Answer:

ANSWER

4x

2

+5

2

x−3

=4x

2

+6

2

x−

2

x−3

=2

2

x(

2

x+3)−(

2

x+3)

=(

2

x+3)(2

2

x−1)

So, the zeros of the polynomial are

(

2

x+3)=0 and (2

2

x−1)=0

x=

2

−3

and x=

2

2

1

x=

2

−3

2

and x=

4

2

Now, the polynomial is 4x

2

+5

2

x−3

Comparing it with ax

2

+bx+c=0, we get a=4, b=5

2

and c=−3

Sum of the zeros =

2

−3

2

+

4

2

=

4

−6

2

+

2

=

4

−5

2

=

a

−b

Product of the zeros =(

2

−3

2

)(

4

2

)

=(

2

−3

)(

4

2

)

=

4

−3

=

a

c

Answered By

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