Question

find the roots of p²-17p+38 using quadratic formula​

Answer 1

Answer:

p² - 17p + 38

by using quadratic formula,

[(-b +or- √(b² - 4ac)] / 2a

[ 17 + or - √( 289 - 4×38)] / 2

[ 17 + or - √137] / 2

solutions are: (17+√137) / 2 and (17-√137) / 2

Answer 2

Answer:

p^2-17p+38=0

comparing the equation with

ax^2+bx+c=0

a=1 , b=-17, c=38

therefore, b^2-4ac

-17^2-4(1) (38)

289-152

b^2-4ac=137