Question

find the roots of quadartic equation 3×square-2 underroot 6x+2=0​

Answer 1

Answer:

Please find the attachment

Answer 2

Answer:

√6/3

Step-by-step explanation:

=>3x^2-(2√6)x+2

using quadratic formula

i.e. -b±√(b^2-4ac)/2a

=>2√6±√(24-24)/6 (D=0)

=>2√6/6

=>√6/3 or √2/√3

both roots are the same as the determinant(D) is zero