Math, asked by rimshaaijaz3, 1 year ago

find the roots of quadratic by factorisation

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Answered by MяMαgıcıαη
1

Answer:

refer to the above attachment for the solution

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Answered by Queen224149
1

 \sqrt{2}  {x}^{2}  + 7x + 5 \sqrt{2}  = 0 \\  \sqrt{2}  {x}^{2}  + 2x + 5x + 5 \sqrt{2}  = 0 \\  \sqrt{2} x(x +  \sqrt{2} ) + 5(x +  \sqrt{2} ) = 0 \\ (x +  \sqrt{2} )( \sqrt{2} x + 5) = 0 \\  \\ x =  -  \sqrt{2}  \: or \:  \frac{ - 5}{ \sqrt{2} }

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