Question

Find the roots of Quadratic equation 16x² – 24x -1 = 0 by using the quadratic formula.
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Answer 1

Step-by-step explanation:

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Answer 2

$x \: = - b + - \frac{ \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = - ( - 24) + - \frac{ \sqrt{ {(24)}^{2} - 4 \times 16 \times ( - 1)} }{2 \times 16} \\ x = 24 + - \frac{ \sqrt{576 + 64} }{32} \\ x = 24 + - \frac{ \sqrt{640} }{32} \\ x = 24 + - \frac{ 8 \sqrt{10} }{32} \\ x = \frac{24}{32} + \frac{ 8\sqrt{10} }{32} \: \: \: \: \: \: \: \: \: \: \: \:or \: \: \: \: \: \: x = \frac{24}{32} - \frac{ 8 \sqrt{10} }{32} \\ x = \frac{24}{32} + \frac{ 8\sqrt{10} }{32} \:\:\: or \:\:\:\: x = \frac{24}{32} - \frac{ 8\sqrt{10} }{32} \\ x = \frac{ 3 + \sqrt{10} }{4} \: \: \: \: \: \: or \: \: \: \: \: \: \: \: x = \frac{ 3 - \sqrt{10} }{4}$