Question

find the roots of Quadratic equation 2 x square - 7x+3=0 by formula method​

Answer 1

Step-by-step explanation:

Given:

$2 {x}^{2} - 7x + 3 = 0$

To find:Roots of quadratic equation by quadratic formula

Solution:

Standard quadratic equation is

$a {x}^{2} + bx + c = 0 \: \: a \neq0$

Quadratic formula:

$\boxed{\bold{x_{1,2}= \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}}}$

here,

a and b are coefficient of x² and x respectively and c is constant.

In the given equation

$a = 2 \\ \\ b = - 7 \\ \\ c = 3$

put these values

$x_{1,2}= \frac{ 7 ± \sqrt{ {( - 7)}^{2} - 4 \times 2 \times 3} }{2 \times 2} \\ \\ \\ = \frac{7 ± \sqrt{49 -2 4} }{4} \\ \\ \\ = \frac{7 ± \sqrt{25} }{4} \\ \\ x_{1,2} = \frac{7 ± 5}{4} \\ \\ x_1 = \frac{12}{4} \\ \\ x_1 = 3 \\ \\ x_2 = \frac{2}{4} \\ \\ x_2 = \frac{1}{2}$

Thus,

Roots of quadratic equation are

3 and 1/2.

Hope it helps you.

To learn more on brainly:

Solve the given quadratic equation:

3x² - 7x + 5 = 0

https://brainly.in/question/7853676