Question

Find the roots of quadratic equation 2x^2+7x+52=0

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

$2 {x}^{2} + 7x + 52 = 0 \\ it \: is \: in \: the \: form \: of \: a {x + bx + c}^{2} \\ so.a = 2 \\ b = 7 \\ c = 52 \\ d = \sqrt{ { {b}^{2} - 4ac}^{} } \\ d = \sqrt{ {7}^{2} - 4 \times 2 \times 52} \\ d = \sqrt{49 - 416} \\ d = \sqrt{ - 367}$

so it doest not have any real root as discriminate is negative