Question

find the roots of quadratic equation 2x square-x-6=0 ... › Math

Answer 1

Answer:

2x²-x-6 = 0

2x²-4x+3x-6 = 0

2x(x-2)-3(x-2) = 0

(2x-3)(x-2) = 0

2x-3 = 0 OR x-2 = 0

2x = 3  OR  x = 2

x = 3/2  OR  x = 2

Answer 2

Answer:

$\text{The roots of the given equation are }2\text{ and }\frac{-3}{2}$

Step-by-step explanation:

Given quadratic equation,

$2x^2-x-6=0$

we have to find the roots of quadratic equation.

$2x^2-x-6=0$

By middle term splitting,

$2x^2-4x+3x-6=0$

Taking 2x common from first two terms and 3 from last two

$2x(x-2)+3(x-2)=0$

Taking (x-2) common

$(x-2)(2x+3)=0$

By the zero product property,

$x-2=0, 2x+3=0$

$x=2, x=\frac{-3}{2}$

$\text{Hence, the roots of the given equation are }2\text{ and }\frac{-3}{2}$