Question

Find the roots of quadratic equation 3x^2-2√6x+2=0

Answer 1

Step-by-step explanation:

First we have to check that this quadratic equation have real roots or not.

Discriminant→b²-4ac where a=3, b=(-2√6), c=2

→(-2√6)²-4×(3)×(2)

→24-24

→0

therefore,b²-4ac=0 that means this equation have real and equal roots.

3x^2-2√6x+2=0

3x²-√6-√6+2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

$x = \frac{ \sqrt{2} }{ \sqrt{3} }$