Question

find the roots of quadratic equation 4√2x^2-7x-√2​

Answer 1

Answer:

Step-by-step explanation:

4√2x²-7x-√2= 4√2x²-8x+x - √2

=4√2x(x-√2) +1 (x - √2)

=(x - √2) (4√2x+1)

Hence root will be

(x - √2)=0, (4√2x+1)=0

X=√2 , x= -1/4√2

Hope it's help you...

Have a great day and thanks for asking dear ❤️❤️❤️

Answer 2

4√2x²-7x-√2= 4√2x²-8x+x - √2

=4√2x(x-√2) +1 (x - √2)

$=(x - √2) (4√2x+1)$

Thus, the cost of one pencil is ₹3.

Hope it helps!

Mark me brainliest!

Hence root will be

(x - √2)=0, (4√2x+1)=0

$X=√2 , x= -1/4√2$