Question

Find the roots of quadratic equation 7x²+4x-20=0. *
OPTIONS-
a.-2,-10/7
b.2,-10/7
c.-2,10/7
d.2,10/7
WILL MARK AS BRAINLIEST​

Answer 1

ANSWER✔

$\sf\implies 7x^2-4x-20=0$

$\sf\dashrightarrow 7x^2+14x-10x-20=0$

$\sf\implies7x(x+2)-10(x+2)=0$

$\sf\implies (7x-10)(x+2)=0$

$\sf\implies 7x-10= 0, x+2=0$

$\sf\implies x= \dfrac{10}{7}, x= -2$

$\sf\therefore x= \dfrac{10}{7} ,-2$

$\large{\boxed{\bf{ \star\:\: x= \dfrac{10}{7} ,-2\:\: \star}}}$

$\large\underline\bold{OPTION\:(C)\:IS\:CORRECT.}$

________________

Answer 2

Answer:

➡ 7x²+4x-20 = 0

=> 7x²+ (14-10)x -20 = 0

=> 7x²+14x-10x -20 = 0

=> 7x(x+2) - 10(x+2) = 0

=> (x+2) (7x-10) = 0

=> (x+2) = 0 | (7x-10) = 0

=> x = -2 | x = 10/7

∴ Hence the value of

$\bold{\</em></strong><strong><em>l</em></strong><strong><em>a</em></strong><strong><em>r</em></strong><strong><em>g</em></strong><strong><em>e</em></strong><strong><em>{\fbox{\color{blue} {</em></strong><strong><em>x</em></strong><strong><em> </em></strong><strong><em>=</em></strong><strong><em> </em></strong><strong><em>-</em></strong><strong><em>2</em></strong><strong><em> </em></strong><strong><em>,</em></strong><strong><em> </em></strong><strong><em>1</em></strong><strong><em>0</em></strong><strong><em>/</em></strong><strong><em>7</em></strong><strong><em>}}}}$

$\mathtt{\bf{\underline{\red{</em></strong><strong><em>Opt</em></strong><strong><em>ion</em></strong><strong><em> (</em></strong><strong><em>C</em></strong><strong><em>)</em></strong><strong><em>\</em></strong><strong><em>:</em></strong><strong><em> </em></strong><strong><em>is\</em></strong><strong><em>:</em></strong><strong><em> </em></strong><strong><em>t</em></strong><strong><em>he</em></strong><strong><em>\</em></strong><strong><em>:</em></strong><strong><em> </em></strong><strong><em>correct\</em></strong><strong><em>:</em></strong><strong><em> </em></strong><strong><em>answ</em></strong><strong><em>er</em></strong><strong><em>\::}}}}$

Step-by-step explanation:

HOPE IT HELP YOU