Find the roots of quadratic equation a²x²-3bx+2b²=0 by quadratic formula
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Hi ,
a²x² - 3abx + 2b² = 0
a²x² - 3abx = - 2b²
divide each term with a² both sides of the
equation ,
x² - 3bx/a = - 2b²/a²
x² - 2 × x × (3b/2a)+(3b/2a)² = ( 3b/2a )² - 2b²/a²
( x - 3b/2a )² = 9b²/4a² - 2b² /a²
= ( 9b² - 4b² ) /a²
= 5b²/a²
x - 3b/2a = ± √ ( 5b²/a² )
x = 3b/2a ± √5 ( b/a )
= [ 3b ± 2√5 b ] / 2a
= ( 3 ± 2√5 )b/ 2a
I hope this helps you.
:)
Step-by-step explanation:
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