Question

Find the roots of quadratic equation by factorization


x2+3√3x +6
​

Answer 1

Answer:

x^2+3√3x+6

Step-by-step explanation:

x^2+3√3x+6=0

x^2-2√3-√3x+6=0

x(x-2√3)-√3(x-2√3)=0

(x-√3)(x-2√3)=0

x=√3and2√3

Answer 2

Answer:

1x6

6. 1,2,3,6

a1. b 3√3. c6

_______

-b+-√b2 - 4ac

___________

2a

roots are

-3√3-√3

________

2

and

-3√3+√3

_______

2

Step-by-step explanation:

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