Question

Find the roots of quadratic equation if exists
$2x^{2} +3x+10=0$

Answer 1

Answer:

X=5

Step-by-step explanation:

The equation x2−3x−10=0 can be solved as

x2−5x+2x−10=0

⇒x(x−5)+2(x−5)=0

⇒(x+2)(x−5)=0

⇒x=−2 and x=5

Answer 2

Answer:

$\huge\bigstar{\underline{\underline{{\sf\ \red{Answer:-}}}}}$

☆ given, x2−3x−10=0

x2−5x+2x−10=0

x(x−5)+2(x−5)=0

(x−5)(x+2)=0

x=−2,5 are the roots of the given equation.