Question

find the roots of quadratic equation x^2+4x-5=0 by quadratic formula​

Answer 1

Answer:

the roots are 2 and -10

Step-by-step explanation:

refer to the attachment

hope i could help u

Answer 2

$\large{\underline{\underline{\mathfrak{Answer :}}}}$

x = 1 or -5

$\rule{200}{0.5}$

$\underline{\underline{\mathfrak{Step-By-Step-Explanation :}}}$

________________________

Given :

Equation : x² + 4x - 5 = 0

________________________

To Find :

• We have to find the roots of equation.

_______________________

Solution :

We know that,

$\large{\boxed{\sf{D = b^2 - 4ac}}}$

$\sf{\implies D = (4)^2 - 4(1)(-5)} \\ \\ \sf{\implies D = 16 -(-20)} \\ \\ \sf{\implies D = 16 + 20} \\ \\ \sf{\implies D = 36}$

$\rule{200}{1}$

Now,

$\large{\boxed{\sf{x = \frac{-b \pm \sqrt{D}}{2a}}}}$

$\sf{\implies x = \frac{- 4\pm \sqrt{36}}{2(1)}} \\ \\ \sf{\implies x = \frac{-4 \pm 6}{2}}$

When positive

$\sf{\implies x = \frac{-4 + 6}{2}} \\ \\ \sf{\implies x = \frac{\cancel{2}}{\cancel{2}}} \\ \\ \sf{\implies x = 1}$

$\rule{150}{2}$

When negative

$\sf{\implies x = \frac{-4 - 6}{2}} \\ \\ \sf{\implies x = \frac{-\cancel{10}}{\cancel{2}}} \\ \\ \sf{\implies x = -5}$