Question

Find the roots of quadratic equation x2 + 2√2x - 6 using quadratic formula

Answer 1

Solution :-

put the Given Equation to 0 .

→ Sridharacharya formula for Solving Quadratic Equation ax² +bx + c = 0 says that,

• x = [ -b±√(b²-4ac) / 2a ]

so,

• a = 1
• b = 2√2
• c = (-6)

then,

→ x = [-2√2 ± √{(2√2)² - 4*1*(-6)}] / 2*1

→ x = [-2√2 ± √(8 + 24)] / 2

→ x = (-2√2 ± √32)/2

→ x = (-2√2 ± 4√2)/2

→ x = (-2√2 + 4√2)/2 , (-2√2 - 4√2)/2

→ x = (2√2/2) , (-6√2/2)

→ x = √2 and (-3√2) (Ans.)

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इस एक्स इक्वल टू रूट 3 प्लस वन डिवाइडेड बाय टू फाइंड द वैल्यू ऑफ एक्स क्यूब प्लस टू एक्स स्क्वायर माइनस 8 एक्स प्लस 7

https://brainly.in/question/20858452

if a^2+ab+b^2=25

b^2+bc+c^2=49

c^2+ca+a^2=64

Then, find the value of

(a+b+c)² - 100 = ...

https://brainly.in/question/16231132