Question

Find the roots of quadratic equation x2-3√5x+10=0
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Answer 1

Step-by-step explanation:

x²-3√5x+10=0

here,

a=1

b= -3√5

c=10

D=b²-4ac

D=(-3√5)²-4×1×10

D= 45-40

D=5

according to Sridharacharya law,

α= (-b±√D)/2a

= {-(-3√5)±√5}/2

= (3√5±√5)/2

= 4√5/2 and 2√5/2

= 2√5 and √5

hence the root of equation be 2√5 & √5

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