Find the roots of quadratic equation x² +x-20
Answers
Answered by
0
Answer:
x^2 + x - 20
=x^2 + (5 - 4) x - 20
=x^2 + 5x - 4x - 20
=x(x+5)-4(x+5)
=(x+5)(x-4)
Answered by
1
Answer :
- Roots of Qudratic Equation are -5 and 4
Given :
- x² + x - 20
To find :
- Roots of Qudratic equation
Solution :
● x² + x - 20 =0
splitting the term
● x² + 5x - 4x - 20 = 0
● x(x + 5) - 4(x + 5) = 0
● (x + 5) (x - 4)
● x + 5 or x - 4 = 0
● x = - 5 0r x = 4
Hence ,
- Roots of Qudratic Equation are -5 and 4
More Explanation:
- Qudratic equation is nothing but an equation that can be written in standard form
- ax² + bx + c = 0
- where a , b and c are real number and a is not equal to zero
Similar questions