Question

Find the roots of quadratic equations 2x²-x-6=0

Answer 1

Answer:

2x^2-x-6=0

2x^2-4x+3x-6=0

2x(x-2) +3(x-2)=0

(2x+3)(x-2)=0

2x+3=0 or x-2=0

x=-3/2 or x= 2

HOPE..!!!IT HELPSSS!!!!

Answer 2

Answer:

x = -3/2 and 2

Step-by-step explanation:

$2x^{2} - x - 6 = 0$

$2x^{2} - 4x +3x - 6 = 0$

$2x(x - 2) + 3(x - 2) = 0$

$(2x + 3) (x - 2) = 0$

x = -3/2 and 2