Question

find the roots of quadratic equqation
$2 \div 5x ^{2} - x - 3 \div 5$
​

Answer 1

Finding the roots :

$2 \div 5x ^{2} - x - 3 \div 5$

Multiply each term by 5 , we get

2x²-5x-3 = 0

Splitting the middle term we

get,

2x² -6x + 1x - 3 = 0

=> 2x(x-3)+1(x-3)=0

=> (x-3)(2x+1)=0

=> x-3 = 0 or 2x+1 = 0

=> x = 3 or x = -1/2

Therefore ,

-1/2 , 3 are roots of given

quadratic equation.

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