Question

find the roots of quadric equation if the exists by using the quadratic
formula : 2x^2-2√2x+1=0​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Answer:

1, 1are the roots

Step-by-step explanation:

$2 {x}^{2} - 2 \sqrt{2} x + 1 = 0$

$2 {x}^{2} - \sqrt{2}x - \sqrt{2}x + 1$

$\sqrt{2} x (x - 1 ) - \sqrt{2} (x - 1)$

$( \sqrt{2} x - \sqrt{2} ) - (x - 1) = 0$

$\sqrt{2} x - \sqrt{2 } = 0 \:or \: x - 1 = 0$

$x = \sqrt{2} \div \sqrt{2} \: \: or \: \: \: x = 1$

$x = 1 \: \: or \: \: x = 1$

Therefore 1, 1 are the roots of the given quadratic equation.