Question

find the roots of quadrqtic equationnof 3(x-4)^-(5x-4)=12​

Answer 1

Answer:

Hope you understand

Step-by-step explanation:

3(x²+16-8x) -5(x-4) = 12

= 3x² + 48 - 24x -5x + 20 = 12,

= 3x² - 29x + 56 = 0,

it can also be written as

3x² - 21x - 8x + 56 = 0,

Now taking common,

3x(x-7) -8(x-7) = 0,

Taking ( x-7 ) common,

(x-7)[3x-8] = 0

Either x -7 = 0 or 3x - 8 =0,

either x = 7 or x = 8/3, But as it is a quadratic , both are the roots of the equation,