Math, asked by Sristi2390, 1 year ago

find the roots of quaratic equation 6x^2=(a-12)x -(a^2+a-6)=0

Answers

Answered by danielochich
6
 6x^2=(a-12)x -(a^2+a-6)=0 

6x^2-(a-12)x +(a^2+a-6)=0

This is a quadratic equation in x

It can be solved by first expanding it, the using the quadratic formula


The quadratic formula is:

x = (-b +/-√b²-4ac)/2


See the image below for the solution:


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Answered by Anonymous
4

Answer:

Step-by-step explanation:

6x^2=(a-12)x -(a^2+a-6)=0

6x^2-(a-12)x +(a^2+a-6)=0

This is a quadratic equation in x

It can be solved by first expanding it, the using the quadratic formula

The quadratic formula is:

x = (-b +/-√b²-4ac)/2

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