find the roots of quartic equation 2xsquare+x-4=0
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Answer:
the roots are -1+√33/4,-1-√33/4
Step-by-step explanation:
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p(x)=2x²+x-4
By formula method,
x=-b±√b²-4ac/2a
=-1±√1+32/4
x= -1-√33/4 or x= -1+√33/4
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