Question

find the roots of te quadratic equations x square - 4 x + 2 =0 using quadratic formula​

Answer 1

EXPLANATION.

Roots of the quadratic equation

x² - 4x + 2 = 0.

To find the discriminant.

D = b² - 4ac

D = (-4)² - 4(1) (2)

D = 16 - 8

D = 8.

X = -b ± √D / 2a.

X = - (-4) ± √8 / 2(1).

X = 4 ± √8 / 2

x = 4 + √8 / 2 Or x = 4 - √8 / 2.

x = 4 + 2√2 / 2 Or x = 4 - 2√2 / 2.

x = 2(2 + √2) /2 Or x = 2(2 - √2) /2.

x = 2 + √2 Or x = 2 - √2.

More information.

D > 0 Or [ b² - 4ac > 0 ]

Roots are real and unequal.

D = 0 Or [ b² - 4ac = 0 ]

Roots are real and equal.

D < 0 Or [ b² - 4ac < 0 ]

Roots are imaginary.