Question

find the roots of
${x}^{2} + 32x - 273$
​

Answer 1

Step-by-step explanation:

Given: x²– 32x – 273 = 0 We can rewrite the given equation as ⇒ x² – 39x + 7x – 273 = 0 ⇒ x( x – 39) + 7(x – 39) = 0 ⇒ ( x – 39)(x + 7) = 0 ∴ Factors of the given quadratic equation are ( x – 39) and (x + 7)

Answer 2

Answer:

Step-by-step explanation:

Given: x2 – 32x – 273 = 0

We can rewrite the given equation as  

⇒ x2 – 39x + 7x – 273 = 0

⇒ x( x – 39) + 7(x – 39) = 0

⇒ ( x – 39)(x + 7) = 0

∴ Factors of the given quadratic equation are  ( x – 39) and (x + 7