find the roots of the 3x2-5x+2=0
Answers
Answer:
1 and 2/3
Step-by-step explanation:
Given: - 3x2-5x+2=0
on comparing this equation with ax2+bx+c=0,
we get; a=3, b=-5 and c=2
Now,
D (Discriminant) = b2−4ac
= (-5)2−4×3×2
=25-24
=1
x= -b±√D/2a
= -(-5) ±√1/2*3
= 5 ± 1/6
Then,
x=5+1/6 =6/6 =1
&
x=5-1/6 = 4/6 = 2/3
find the roots of the 3x2-5x+2=0
Calculate the product
Collect like terms by subtracting their coefficients
Then, Subtract the numbers
When the term has a coefficient of 1, it doesn't have to be written.
Because the coefficient 1 doesn't have to be written because it's doesn't affect the value of the term.
Move constant to the right by adding it's opposite to both sides
I want to move the constant to the right because mathematicians agreed upon a convention that constants in equations and inequalities always need to be on the right-hand side.
Then, the opposite term needs to be added to both sides to preserve the relation between the sides, according to the addition and subtraction property of equality/inequality.
Since the opposite add up to zero, remove them from the expression
Because the Inverse Property of Addition states that two opposite numbers add up to zero 0.
Since adding or subtarcting 0 doesn't change the value of the expression, we can just remove it.
When adding or subtarcting 0, the quantity does not change
hope this help!