Math, asked by sudhakaregagks, 5 months ago

find the roots of the equation 2x^2-5x+3=0 and verify whether 1 and 3/2 are the roots of the equation.​

Answers

Answered by yadavnobita13
46

x=1,x=3/2

Step-by-step explanation:

2x²-5x+3=0

0=2x²-3x-2x+3

0=x(2x-3)-1(2x-3)

0=(x-1)(2x-3)

if x-1=0

x=1

if 2x-3=0

then 2x=3

x=3/2

Verification:

1)L.H.S.=2(1)²-5(1)+3

=2-5+3

=5-5

=0=R.H.S

2)L.H.S.=2(3/2)²-5(3/2)+3

={2(9/4)}-{15/2}+3

=9/2-15/2+3

=-6/2+3

=-3+3

=0=R.H.S.

Hence Verified

Answered by amansharma264
65

EXPLANATION.

roots of the equation = 2x² - 5x + 3 = 0

verify wheather 1 and 3/2 are the roots of the

equation.

Factories into middle term split.

= 2x² - 5x + 3 = 0

= 2x² - 3x - 2x + 3 = 0

= x ( 2x - 3 ) - 1 ( 2x + 3 ) = 0

= ( x - 1 ) ( 2x - 3 ) = 0

= x = 1 and x = 3/2.

sum = 1 + 3/2

= 2 + 3 /2 = 5/2

products = 1 X 3/2 = 3/2.

sum of zeroes of quadratic equation.

= a + b = -b/a

= a + b = 5/2

products of zeroes of quadratic equation.

= ab = c/a

= ab = 3/2.

More information.

= D > 0 Or [ b² - 4ac > 0 ]

roots are real and unequal.

= D = 0 Or [ b² - 4ac = 0 ]

roots are real and equal.

= D < 0 or [ b² - 4ac < 0 ]

roots are imaginary.

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