find the roots of the equation 2x^2-x+1/8=0 by factorisation method
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by factorisation method
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2x²×1/8 =x²/4 = -x/2 * -x/2
2x² -x + 1/8 =0
2x² -x/2 -x/2 +1/8 =0
x/2(4x -1)-1/8(4x-1) =0
(x/2 -1/8)(4x-1) =0
x= 1/4, 1/4
or Alternate method
multiply whole equation with 2
4x²-2x +1/4 =0
(2x)²-2*1/2*2x + (1/2)² =0
(2x-1/2)² =0
x= 1/4, 1/4
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