Question

find the roots of the equation 2x^4-3x^2+1=0 ​

Answer 1

Answer:

Simple enough . Solutions a given quadratic equation ax^2 + bx + c = 0 is given by

x = {- b +/- sqrt(b^2 - 4ac)}/2a. Therefore for the given quadratic 3x^2 + 2x + 4 = 0, solutions are given by; x = {- 2 +/- sqrt(4 - 48)}/6 or

6x = -2 +/- 2 i sqrt(11) ==>

x = (-1/3)[1 - i sqrt(11)] and x = (-1/3)[1 +i sqrt(11)].

Step-by-step explanation:

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