find the roots of the equation
2Xsquare+3X+2=0
plz answer me fast
Answers
Answered by
1
2x^2+3x+2=0
x= -(i/4)(Root 7-3i) , (1/4)(Root 7+3i)
Answered by
1
Answer:
x= -2 or 1/2
Step-by-step explanation:
2x^2+3x-2=0
=>2x^2+4x-x-2=0
=>2x(x+2)-1(x+2)
=>(x+2) (2x-1)
so, x= -2 or 1/2
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