Question

Find the roots of the equation: √3 x²-2√2x -2√3 =0​

Answer 1

Answer:

Given:-

The equation is √3x² - 2√2x -2√3

To Find:-

The roots of the equation

solution:-

√3x² - 2√2x -2√3

= √3x² -( 3 -1 )√2x -2√3

= √3x² - 3√2x + √2x - 2√3

= √3x ( x - √6) + √2( x - √6)

= ( x-√6) ( √3x +√2)

so, either

x - √6 = 0

x = √6

or,

√3x +√2 =0

√3x = -√2

x = -√2/√3

Therefore roots are √6 and -√2/√3