Question

find the roots of the equation √3x2-2 √2x-2√3 =0​

Answer 1

Heya !!

The given equation is √3X² - 2√2X - 2√3 = 0

Here,

a = √3 , b = -2√2 and c = -2√3.

Discriminant ( D ) = B²-4AC

=> (-2√2)² - 4 × √3 × -2√3

=> 8 + 24

=> 32

✓D = √32 = √2 × 2 × 2 × 2 × 2 = 4√2.

Roots of the given equation are : -B + √D/2A and -B - √D/2A

=> - (-2✓2) + 4√2 / 2√3 and -(-2√2) - 4√2/2√3

=> ( 2√2 + 4√2 ) /2√3 and (2√2 - 4√2 ) /2√3

=> ( 6√2/2√3 ) And ( -2√2/2√3 ).

=> ( 3√2/√3 ) and ( -√2/√3)

=> ( √3 × √3 × √2/✓3) and ( -√2/√3)

=> ( √3 × √2 ) and ( -√2/✓3)

=> ( √6 ) and ( -√2/√3).

plz give !e a thanks if this answer helps you

Answer 2

Answer:

√3x²-2√2x-2√3 =0

√3x²-(3√2-√2)x-2√3 =0

√3x²-3√2x+√2x-2√3 =0

√3x(x-√3.√2) + √2 ( x-√3.√2) =

(√3x+√2) ( x-√6) =0

√3x-√2=0 , x-√6 =0

x= √2/√3 x= √6

hope it will help you