Question

find the roots of the equation 4x^2-3x-3=0​

Answer 1

Answer:

use dharacharya rule

Step-by-step explanation:

we have the equation 4x^2 -3x -3

x= -b + √(b^2 - 4ac)/2a

x= 3+ √(9 +48)/8

x= 3+√57/8

x= (3+57)/8. (3 - √57)/8

Answer 2

AnSwEr

${\tt{\red{\underline{\large{Given}}}}}$

• A quadratic polynomial
• 4x²-3x-3

${\sf{\green{\underline{\large{To\:find}}}}}$

• Roots of the Equation

${\sf{\pink{\underline{\Large{Explanation}}}}}$

$\tt\: Quadratic\:formula\dfrac{-b\pm\sqrt{d}}{2a}\\or$

$\tt\:D=b^2-4ac$

puttIng the value

• Here a = 4 b= 3 and c = 3

D= b²-4ac

=>D=9+48

=>D=57

Here D=57

$\tt\: Quadratic\:formula\dfrac{-b\pm\sqrt{d}}{2a}$

$\tt\:X=\dfrac{-3\pm\sqrt{57}}{8}$

Taking X as positive

$\tt\:X=\dfrac{-3+\sqrt{57}}{8}$

Taking X as Negative

$\tt\:X=\dfrac{-3-\sqrt{57}}{8}$