Find the roots of the equation 4x+3y = 12
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Given equation is 4x + 3y =12
On putting x = 0 in Eq. (i), we get
4(0) +3y =12 ⇒ 3y =12
⇒ y = 12 / 3 = 4
So, (0, 4) is a solution of given equation.
On putting y = 0 in Eq. (i), we get
4x+ 3 (0) =12 ⇒ 4x =12
x = 12 / 4 =3
So, (3, 0) is a solution of given equation.
On putting x =1 in Eq. (i), we get
4(1) + 3y=12 ⇒ 3y = 12 - 4 = 8 ⇒ y = 8 / 3
So, (1,8 / 3) is another solution of the given equation.
Further, putting x = 2 in Eq. (i), we get
4(2) + 3y = 12 ⇒ 3y = 12 - 8 = 4 ⇒ y = 4 / 3
So, (2, 4 / 3) is also a solution of the given equation.
Hence the four solutions of given equation are (0, 4), (3, 0), (1, 8 / 3) and (2,4 / 3).
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