Question

find the roots of the equation 5X^2-6X-2=0 by the method of completing square

Answer 1

5x^2 -6x -2 = 0

x^2 -(6/5)x -(2/5) = 0

(x)^2 - [2.(3/5).x] + (3/5)^2 - (3/5)^2 -(2/5) = 0

[x-(3/5)]^2 = (2/5)+(9/25)

[x-(3/5)]^2 = (19/25)

x-(3/5) = √19/5

x = (3/5) ± √19/5

Roots of the equation are

x = [3+(√19)]/5
& x = [3-(√19)]/5
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