Question

find the roots of the equation 5x²-5x-6=0 by the method of completing the square​

Answer 1

Step-by-step explanation:

that is the correct process for the question

Answer 2

Answer:

Step-by-step explanation:

5x²-5x-6=0

completing formula =$[x+(b/2a )]^2-(b/2a)^2+c/a=0$

from the equation , a = 5, b = -5, c = -6

⇒[x+(-5/2(5)]^2 - (-5/2(5) )^2 + (-6/5) = 0

⇒[x+(-1/2)]^2 - (-1/2)^2 + (-6/5) =0

⇒[x - (1/2)]^2 + (1/4) - (6/5) =0

⇒[x - (1/2)]^2 + (1/4) - (6/5) = 0

⇒[x - (1/2)]^2 + (-19/20) =0

⇒[x - (1/2)]^2 - (19/20) = 0

⇒[x - (1/2)]^2 = (19/20)

⇒√ [x - (1/2)]^2 = ±√ (19/20)

⇒(x - (1/2) ) = ±(√19/2√5)

⇒x=(1/2) + (19/20)   OR   x=(1/2) - (19/20)

⇒x = 29/20   OR   x = -9/20

⇒