find the roots of the equation 5xsquare-6x-2=0 in completing square method
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5x^2 - 6x - 2 = 0
5x^2 - 6x = 2
x^2 - 6x/5 = 2/5
x^2 - 6x/5 + (6/10)^2 = 2/5 + (6/10)^2
(x-6/10)^2 =2/5 + 36/100
(x-6/10)^2 =(40+36)/100
(x-6/10)^2 =76/100
x-6/10 = plus minus root76/10
x = 6/10 plus minus 2root19/10
First root = (6+2 root 19)/10
Second root = (6-2 root 19)10
5x^2 - 6x = 2
x^2 - 6x/5 = 2/5
x^2 - 6x/5 + (6/10)^2 = 2/5 + (6/10)^2
(x-6/10)^2 =2/5 + 36/100
(x-6/10)^2 =(40+36)/100
(x-6/10)^2 =76/100
x-6/10 = plus minus root76/10
x = 6/10 plus minus 2root19/10
First root = (6+2 root 19)/10
Second root = (6-2 root 19)10
dwijit:
thanks
why do you add (6/10) square on both sides
The process of making perfect square
First Transfer the constant term in RHS
Then divide the whole equation by the coficient of x square
Then add the square of coficient of x to both sides
Then you will get perfect square in LHS
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