Question

find the roots of the equation a sq+5a-6=0 using quadratic formula.​

Answer 1

$\huge\underline\mathrm{Question-}$

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find the roots of the equation a² + 5a - 6 = 0 using quadratic formula.

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$\huge\underline\mathrm{Answer-}$

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Roots of the given equation are 1 and -6.

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$\huge\underline\mathrm{Solution-}$

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a² + 5a - 6 = 0

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Comparing with ax² + bx + c = 0, we get,

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a = 1

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b = 5

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c = -6

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Firstly, we have to find the discriminant.

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D = b² - 4ac

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$\mapsto$ D = (5)² - 4(1)(-6)

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$\mapsto$ D = 25 + 24

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$\mapsto$ D = 49

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Now, quadratic formula :

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$\large{\boxed{\rm{\red{Roots=\dfrac{-b±\sqrt{D}}{2a}}}}}$

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Putting the values,

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$\mapsto$ Roots (a) = $\dfrac{-5±\sqrt{49}}{2(1)}$

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$\mapsto$ Roots (a) = $\dfrac{-5+7}{2}$ and $\dfrac{-5-7}{2}$

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$\mapsto$ Roots (a) = $\cancel{\dfrac{2}{2}}$ and $\cancel{\dfrac{-12}{2}}$

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$\mapsto$ Roots (a) = 1 and -6

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$\therefore$ Roots of the given equation are 1 and -6.

Answer 2

Answer refer to attachment..

hope it helps you (. ❛ ᴗ ❛.)