find the roots of the equation by using formula x2+2x-143=0
Answers
Answered by
79
x² + 2x - 143 = 0
=> x² + 13x - 11x - 143 = 0
=> x(x+13) - 11(x+13) = 0
=> (x - 11)(x + 13) = 0
=> x = 11, -13
=> x² + 13x - 11x - 143 = 0
=> x(x+13) - 11(x+13) = 0
=> (x - 11)(x + 13) = 0
=> x = 11, -13
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Answered by
15
Given equation is x^2+2x-143=0
discriminant b^2-4ac=4-4(1)(-143)=positive value
it has real roots
-143=13×-2
x^2+13x-11x-143=0
x(x+13)-11(x+13)=0
x=11 or -13
Hence roots are 11 and -13
hope it helps
discriminant b^2-4ac=4-4(1)(-143)=positive value
it has real roots
-143=13×-2
x^2+13x-11x-143=0
x(x+13)-11(x+13)=0
x=11 or -13
Hence roots are 11 and -13
hope it helps
nice
kk
which class?
11th
and u...?
10th
u r younger than me
yep
hmm
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