Question

find the roots of the equation m/x-n+n/x-m=2;x=m,n​

Answer 1

(m/n)x^2 +(n/m) = 1-2x

(m/n)x^2 +2x =1-(n/m)

x^2 +2(n/m)x =n/m -n^2/m^2

add (n/m)^2 both side

x^2 +2.(n/m).x +(n/m)^2 =n/m -n^2/m^2+n^2/m^2

(x+n/m)^2 =n/m

take square root ,

x + n/m = +_ √(n/m)

x = -n/m +_√(n/m)