Find the roots of the equation=
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Answers
Answered by
4
Hi here is your answer.
3x²-5x+2=0
3x²-3x-2x+2=0
3x(x-1)-2(x-1)=0
(x-1)(3x-2)=0
so,
x=1 and x=2/3
i Hope it is helpful
3x²-5x+2=0
3x²-3x-2x+2=0
3x(x-1)-2(x-1)=0
(x-1)(3x-2)=0
so,
x=1 and x=2/3
i Hope it is helpful
Answered by
3
Hi dear !!!
here is your answer !!!
3x² -5x +2 = 0
using sridharacharya formula
-b ± √ b² -4ac /2a
5 ± √ 5²-4×3 ×2 /2×3
=> 5± √ 25 -24 / 6
5 ±1 /6
hence two possible values are
1 , 2/3
hope it help you dear !!!
thanks !!
here is your answer !!!
3x² -5x +2 = 0
using sridharacharya formula
-b ± √ b² -4ac /2a
5 ± √ 5²-4×3 ×2 /2×3
=> 5± √ 25 -24 / 6
5 ±1 /6
hence two possible values are
1 , 2/3
hope it help you dear !!!
thanks !!
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