Math, asked by ameenfb11, 1 year ago

find the roots of the equation
 {x}^{2}  + x - p(p + 1) = 0
if p is a constant.

NOTE:the question is from quadratic equations and not from polynomials...so plz guve a relevant answer.

ASAP​

Answers

Answered by Anonymous
0

x^2+x-p(p+1)=0

x^2+(p+1)x -px- p(p+1)=0

x(x+p+1)-p(x+p+1)=0

so x=p

and x= -(p+1)

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