Math, asked by sharmaraju331, 1 year ago

find the roots of the equation under root 7 x square - 6 x minus 13 under root 7 is equal to zero

Answers

Answered by mathupto12
49
It will definitely help you
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Answered by vaduz
33

Answer: -\sqrt{7} and \frac{13}{\sqrt{7} }


Step-by-step explanation:

given equation is

\sqrt{7}  x^{2} -6x-13\sqrt{7} =0\\\sqrt{7}  x^{2}-13x+7x-13\sqrt{7} =0\\x(\sqrt{7}x-13)+\sqrt{7}(\sqrt{7}x-13)=0\\  (\sqrt{7}x-13)(x+\sqrt{7}=0

so the value of x = -\sqrt{7} and \frac{13}{\sqrt{7} }


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