Question

find the roots of the equation under root 7 x square - 6 x minus 13 under root 7 is equal to zero

Answer 1

It will definitely help you

Answer 2

Answer: $-\sqrt{7} and \frac{13}{\sqrt{7} }$

Step-by-step explanation:

given equation is

$\sqrt{7}  x^{2} -6x-13\sqrt{7} =0\\\sqrt{7}  x^{2}-13x+7x-13\sqrt{7} =0\\x(\sqrt{7}x-13)+\sqrt{7}(\sqrt{7}x-13)=0\\  (\sqrt{7}x-13)(x+\sqrt{7}=0$

so the value of x = $-\sqrt{7} and \frac{13}{\sqrt{7} }$