Question

Find the roots of the equation (x+3) (x-3) = 25

Pls solve
it's urgent

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Answer 1

Answer:

(x+3)(x−3)=25

x²-9=25

x²=25+9

x²=34

x=+-√34

hence

x=-√34 x=√34

Answer 2

$\huge\boxed{\underline{\underline{\green{\tt Solution}}}} </p><p>$

We are aware of the identity that

$\: (a + b)(a - b) = {a}^{2} - {b}^{2} \: \: ...........(1)$

Now the given equation is

$(x + 3)(x - 3) = 25$

Using the Identity in (1) we get

${x}^{2} - {3}^{2} = 25$

$\implies \: {x}^{2} - 9 = 25$

$\implies \: {x}^{2} = 34$

$\implies \: {x}^{2} - 34 = 0$

$\implies \: {x}^{2} - {( \sqrt{34} )}^{2} = 0$

Using the Identity in (1) we get

$( x+ \sqrt{34} )(x - \sqrt{34} ) = 0$

We know that if the product of two real numbers are zero then either of them is zero

So

$x + \sqrt{34} = 0 \: \: \: \: \: \: or \: \: \: \: \: x - \sqrt{34} = 0$

Now

$x + \sqrt{34} = 0 \: \: \: gives \: \: x \: = - \sqrt{34}$

Also

$x - \sqrt{34} = 0 \: \: gives \: \: x \: = \sqrt{34}$

So the required roots of the equation are

$- \sqrt{34} \: \: \: , \: \: \: \sqrt{34}$

$</p><p>\displaystyle\textcolor{red}{Please \: Mark \: it \: Brainliest}$