Question

find the roots of the equation X square - 2 x minus 8 is equal to zero using the quadratic formula​

Answer 1

Step-by-step explanation:

${x}^{2} - 2x - 8 = 0$

a = 1

b = -2

c = -8

$x = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{2 + \sqrt{ { - 2}^{ 2} - 4 \times 1 \times - 8 } }{2 \times 1}$

$x = \frac{2 + \sqrt{ {4 + 32}} }{2}$

$x = \frac{2 + \sqrt{36} }{2}$

Taking (+) sign

$x = \frac{2 + 6}{2} = \frac{8}{2}$

$x = 4$

Taking (-) sign

$x = \frac{2 - 6}{2} = \frac{ - 4}{2} = - 2$

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Answer 2

Answer:

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