Question

find the roots of the equation x²+2√2x-6= 0​

Answer 1

Heya❤

$x {}^{2} + 2 \sqrt{2}x - 6 \\ x {}^{2} + 3 \sqrt{2} x - \sqrt{2} x - 6 \\x(x + 3 \sqrt{2} ) - \sqrt{2} (x + 3 \sqrt{2} ) \\ (x - \sqrt{2} )(x + 3 \sqrt{2} ) \\ \\ now... \\ x - \sqrt{2} = 0 \\ x = \sqrt{2} \\ \\ and \\ \\ x + 3 \sqrt{2} = 0 \\ x = - 3 \sqrt{2}$

Hope it helps you

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Answer 2

Answer:

Step-by-step explanation:

on putting minus3root 2 & root 2equation satisfied so. two ans ok

explaination given above