Question

find the roots of the equation x2-2(a2+b2)x+(a2-b2)2=0​

Answer 1

Step-by-step explanation:

think the question must be :

find the roots of the equation: x² - 2(a²+b²)x + (a²-b²)² = 0

=>x² - (a+b)²x - (a-b)²x + (a+b)²(a-b)² = 0

=>x[x - (a+b)²] - (a-b)²[x - (a+b)²] = 0

=>[x - (a+b)²][x - (a-b)²] = 0

=>x = (a+b)² , (a-b)²

However if the question was: x² - 2(a²+b²)x + (a²-b²) = 0

Then apply quadratic formula...

x = [2(a²+b²) ± √{4(a²+b²)² - 4(a²-b²)}]/2

= [2(a²+b²) ± 2√{(a²)² + (b²)² - 2a²b² - a² + b²)}]/2

This would be the answer.

However I don't think this is the question. It should the one I mentioned before, else the answer is leading to many complications.

If my answer is helpful please chose as best answer.

Answer 2

Hope it helps you

Here, we can also use quadratic formula method but if we will use then we find so difficult problems so that's why i used this formula and this is the easiest way to solve this type of questions!!!